
Assuming that the ball does not hit the floor within the first …
Assuming that the ball does not hit the floor within the first second of motion, which of these graphs represents the speed of the ball plotted against time?
Question #59f9a - Socratic
t = 22.7 "s" WARNING: LONG-ish ANSWER What we'll essentially be calculating is the sum of three different times: the time it takes to accelerate to the given maximum speed, the time it …
How long will it take a car to accelerate from 14.2 m/s to ... - Socratic
May 11, 2018 · Use equation of motion v = u + at Where v = Final velocity u = Initial velocity a = Acceleration t = Time taken change velocity from u to v t = v − u a = 24.5 m/s – 14.2 m/s 2.2 …
Answers created by David G. - Socratic
The graph shows the variation with distance #d# of the displacement #x# of points in the medium. What is the average speed of a point in the medium during one full oscillation? A particle of …
Answers edited by Nallasivam V - Socratic
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Car travels from point A to point B at a constant speed of
Jan 29, 2018 · I think it is 0km"/"h. First of all, I don't think that acceleration has to do anything with this. Anyways, let's get right into the problem. Average velocity is defined by the equation: …
If a 2 kg object moving at 10 ms^-1 slows to a halt after ... - Socratic
\mu=F_"frict"/ (mg)=4/ (2xx9.8)=0.20 The object's final velocity will be v=0 ms^-1, the initial velocity u=10 ms^-1 and the distance 25 m. We can use this to find the object's acceleration …
If a #3 kg# object moving at #8 m/s# slows to a halt after
#"The slope of velocity-time graph gives deceleration of object."#
Please help me solve for the average of speed and the ... - Socratic
Please see below. Average speed is total distance covered divided by total time taken; and average accelaration is change in velocity divided by total time taken. (A) As bicycle takes 15 …
Choose the graph of this quadratic inequality? | Socratic
Apr 24, 2018 · The answer is the first graph: Given y^2-x^2/9 >= 1 We know that the equation: y^2-x^2/9 = 1 Is a hyperbola with a vertical transverse axis; this eliminates graphs 3 and 4 …